2[6x-5(x-3)]+4=40

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Solution for 2[6x-5(x-3)]+4=40 equation:


Simplifying
2[6x + -5(x + -3)] + 4 = 40

Reorder the terms:
2[6x + -5(-3 + x)] + 4 = 40
2[6x + (-3 * -5 + x * -5)] + 4 = 40
2[6x + (15 + -5x)] + 4 = 40

Reorder the terms:
2[15 + 6x + -5x] + 4 = 40

Combine like terms: 6x + -5x = 1x
2[15 + 1x] + 4 = 40
[15 * 2 + 1x * 2] + 4 = 40
[30 + 2x] + 4 = 40

Reorder the terms:
30 + 4 + 2x = 40

Combine like terms: 30 + 4 = 34
34 + 2x = 40

Solving
34 + 2x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-34' to each side of the equation.
34 + -34 + 2x = 40 + -34

Combine like terms: 34 + -34 = 0
0 + 2x = 40 + -34
2x = 40 + -34

Combine like terms: 40 + -34 = 6
2x = 6

Divide each side by '2'.
x = 3

Simplifying
x = 3

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